35x^2-140x=0

Solution for 35x^2-140x=0 equation:

35x^2-140x=0

a = 35; b = -140; c = 0;
Δ = b2-4ac
Δ = -1402-4·35·0
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-140}{2*35}=\frac{0}{70}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+140}{2*35}=\frac{280}{70}
=4
$